General solutions of matrix equation AXBT + CYDT = T(求解矩阵方程AXBT+CYDT=T的一般解)

对于矩阵方程AXBT + CYDT = T,将其作为在列分块E= [A,C]和F= [B,D]下EZFT = T的块对角约束问题,其中Z=diag(X,Y).通过QR和CS分解,从无约束矩阵方程EZFT = T的通解中得到相应块对角解的简洁表达式.

Bibliographic Details
Main Author: LUJun-feng(卢俊峰)
Format: Article
Language:zho
Published: Zhejiang University Press 2007-07-01
Series:Zhejiang Daxue xuebao. Lixue ban
Subjects:
Online Access:https://doi.org/zjup/1008-9497.2007.34.4.361-363

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