Solving the (n2 − 1)-Puzzle with 8/3 n3 Expected Moves
It is shown that the greedy algorithm for the \((n^2-1)\)-puzzle makes \(\tfrac{8}{3}n^3 +O(n^2)\) expected moves. This analysis is verified experimentally on 10,000 random instances each of the \((n^2-1)\)-puzzle for \(4 \leq n \leq 200\).
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Format: | Article |
Language: | English |
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MDPI AG
2015-07-01
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Series: | Algorithms |
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Online Access: | http://www.mdpi.com/1999-4893/8/3/459 |
Summary: | It is shown that the greedy algorithm for the \((n^2-1)\)-puzzle makes \(\tfrac{8}{3}n^3 +O(n^2)\) expected moves. This analysis is verified experimentally on 10,000 random instances each of the \((n^2-1)\)-puzzle for \(4 \leq n \leq 200\). |
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ISSN: | 1999-4893 |