| Summary: | The bidentate 1,3,4-thiadiazole ligand, namely, 2,5-bis(2-pyridyl)-1,3,4-thiadiazole (denoted L), untested as a polydentate ligand, has been found to form the monomeric title complex, [Ni(C12H8N4S)2(H2O)2](BF4)2. The complex shows an octahedral environment of the nickel cation in which the Ni2+ ion is located on a center of symmetry, linked to two ligands and two water molecules. In this 1:2 complex (one metal for two organic ligands) each thiadiazole ligand uses one pyridyl and one thiadiazole N atom for chelate binding. In the second pyridyl substituent, the N atom is oriented towards the same direction as the S atom of the 1,3,4-thiadiazole ring. The mean plane of the thiadiazole and pyridyl rings linked to the nickel cation forms a dihedral angle with the other pyridine ring of 18.63 (8)°. The tetrafluoridoborate ions can be regarded as free anions in the crystal lattice. Nevertheless, they are involved in an infinite two-dimensional network parallel to (overline{1}01) through O—H...F hydrogen bonds.
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