On cogrowth function of algebras and its logarithmical gap

Let $A \cong k\langle X \rangle / I$ be an associative algebra. A finite word over alphabet $X$ is $I$-reducible if its image in $A$ is a $k$-linear combination of length-lexicographically lesser words. An obstruction is a subword-minimal $I$-reducible word. If the number of obstructions is finite t...

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Main Authors: Kanel-Belov, Alexei Ya., Melnikov, Igor, Mitrofanov, Ivan
Format: Article
Language:English
Published: Académie des sciences 2021-04-01
Series:Comptes Rendus. Mathématique
Online Access:https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.170/
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author Kanel-Belov, Alexei Ya.
Melnikov, Igor
Mitrofanov, Ivan
author_facet Kanel-Belov, Alexei Ya.
Melnikov, Igor
Mitrofanov, Ivan
author_sort Kanel-Belov, Alexei Ya.
collection DOAJ
description Let $A \cong k\langle X \rangle / I$ be an associative algebra. A finite word over alphabet $X$ is $I$-reducible if its image in $A$ is a $k$-linear combination of length-lexicographically lesser words. An obstruction is a subword-minimal $I$-reducible word. If the number of obstructions is finite then $I$ has a finite Gröbner basis, and the word problem for the algebra is decidable. A cogrowth function is the number of obstructions of length $\le n$. We show that the cogrowth function of a finitely presented algebra is either bounded or at least logarithmical. We also show that an uniformly recurrent word has at least logarithmical cogrowth.
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spelling doaj.art-b7b1ccb6addc4fc0bc68288bccabe84a2023-10-24T14:18:42ZengAcadémie des sciencesComptes Rendus. Mathématique1778-35692021-04-01359329730310.5802/crmath.17010.5802/crmath.170On cogrowth function of algebras and its logarithmical gapKanel-Belov, Alexei Ya.0Melnikov, Igor1Mitrofanov, Ivan2Bar Ilan University, Ramat-Gan, IsraelMoscow Institute of Physics and Technology, Dolgoprudny, RussiaC.N.R.S., École Normale Superieur, PSL Research University, FranceLet $A \cong k\langle X \rangle / I$ be an associative algebra. A finite word over alphabet $X$ is $I$-reducible if its image in $A$ is a $k$-linear combination of length-lexicographically lesser words. An obstruction is a subword-minimal $I$-reducible word. If the number of obstructions is finite then $I$ has a finite Gröbner basis, and the word problem for the algebra is decidable. A cogrowth function is the number of obstructions of length $\le n$. We show that the cogrowth function of a finitely presented algebra is either bounded or at least logarithmical. We also show that an uniformly recurrent word has at least logarithmical cogrowth.https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.170/
spellingShingle Kanel-Belov, Alexei Ya.
Melnikov, Igor
Mitrofanov, Ivan
On cogrowth function of algebras and its logarithmical gap
Comptes Rendus. Mathématique
title On cogrowth function of algebras and its logarithmical gap
title_full On cogrowth function of algebras and its logarithmical gap
title_fullStr On cogrowth function of algebras and its logarithmical gap
title_full_unstemmed On cogrowth function of algebras and its logarithmical gap
title_short On cogrowth function of algebras and its logarithmical gap
title_sort on cogrowth function of algebras and its logarithmical gap
url https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.170/
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AT melnikovigor oncogrowthfunctionofalgebrasanditslogarithmicalgap
AT mitrofanovivan oncogrowthfunctionofalgebrasanditslogarithmicalgap