On a Pólya’s inequality for planar convex sets

In this short note, we prove that for every bounded, planar and convex set $\Omega $, one has \[ \frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}\le \frac{\pi ^2}{12}\cdot \left(1+\sqrt{\pi }\frac{r(\Omega )}{\sqrt{|\Omega |}}\right)^2, \] where $\lambda _1$, $T$, $r$ and $|{\,\cdot \,}|$ are the fir...

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Main Author: Ftouhi, Ilias
Format: Article
Language:English
Published: Académie des sciences 2022-03-01
Series:Comptes Rendus. Mathématique
Online Access:https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.292/
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author Ftouhi, Ilias
author_facet Ftouhi, Ilias
author_sort Ftouhi, Ilias
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description In this short note, we prove that for every bounded, planar and convex set $\Omega $, one has \[ \frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}\le \frac{\pi ^2}{12}\cdot \left(1+\sqrt{\pi }\frac{r(\Omega )}{\sqrt{|\Omega |}}\right)^2, \] where $\lambda _1$, $T$, $r$ and $|{\,\cdot \,}|$ are the first Dirichlet eigenvalue, the torsion, the inradius and the volume. The inequality is sharp as the equality asymptotically holds for any family of thin collapsing rectangles.As a byproduct, we obtain the following bound for planar convex sets \[ \frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}\le \frac{\pi ^2}{12}\left(1+\frac{2\sqrt{2(6+\pi ^2)}-\pi ^2}{4+\pi ^2}\right)^2\approx 0.996613\dots \] which improves Polyá’s inequality $\frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}<1$ and is slightly better than the one provided in [3].The novel ingredient of the proof is the sharp inequality \[ \lambda _1(\Omega )\le \frac{\pi ^2}{4}\cdot \left(\frac{1}{r(\Omega )}+\sqrt{\frac{\pi }{|\Omega |}}\right)^2, \] recently proved in [8].
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spelling doaj.art-bfeeb284e218418d91190a6d53f0293f2023-10-24T14:19:47ZengAcadémie des sciencesComptes Rendus. Mathématique1778-35692022-03-01360G324124610.5802/crmath.29210.5802/crmath.292On a Pólya’s inequality for planar convex setsFtouhi, Ilias0Friedrich-Alexander-Universität Erlangen-Nürnberg, Department of Mathematics, Chair of Applied Analysis (Alexander von Humboldt Professorship), Cauerstr. 11, 91058 Erlangen, GermanyIn this short note, we prove that for every bounded, planar and convex set $\Omega $, one has \[ \frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}\le \frac{\pi ^2}{12}\cdot \left(1+\sqrt{\pi }\frac{r(\Omega )}{\sqrt{|\Omega |}}\right)^2, \] where $\lambda _1$, $T$, $r$ and $|{\,\cdot \,}|$ are the first Dirichlet eigenvalue, the torsion, the inradius and the volume. The inequality is sharp as the equality asymptotically holds for any family of thin collapsing rectangles.As a byproduct, we obtain the following bound for planar convex sets \[ \frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}\le \frac{\pi ^2}{12}\left(1+\frac{2\sqrt{2(6+\pi ^2)}-\pi ^2}{4+\pi ^2}\right)^2\approx 0.996613\dots \] which improves Polyá’s inequality $\frac{\lambda _1(\Omega )T(\Omega )}{|\Omega |}<1$ and is slightly better than the one provided in [3].The novel ingredient of the proof is the sharp inequality \[ \lambda _1(\Omega )\le \frac{\pi ^2}{4}\cdot \left(\frac{1}{r(\Omega )}+\sqrt{\frac{\pi }{|\Omega |}}\right)^2, \] recently proved in [8].https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.292/
spellingShingle Ftouhi, Ilias
On a Pólya’s inequality for planar convex sets
Comptes Rendus. Mathématique
title On a Pólya’s inequality for planar convex sets
title_full On a Pólya’s inequality for planar convex sets
title_fullStr On a Pólya’s inequality for planar convex sets
title_full_unstemmed On a Pólya’s inequality for planar convex sets
title_short On a Pólya’s inequality for planar convex sets
title_sort on a polya s inequality for planar convex sets
url https://comptes-rendus.academie-sciences.fr/mathematique/articles/10.5802/crmath.292/
work_keys_str_mv AT ftouhiilias onapolyasinequalityforplanarconvexsets