Product decompositions of quasirandom groups and a Jordan type theorem

We first note that a result of Gowers on product-free sets in groups has an unexpected consequence: If k is the minimal degree of a representation of the finite group G, then for every subset B of G with $|B| > |G| / k^{1/3}$ we have B^3 = G. We use this to obtain improved versions of recen...

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Auteurs principaux: Nikolov, N, Pyber, L
Format: Journal article
Langue:English
Publié: 2007
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author Nikolov, N
Pyber, L
author_facet Nikolov, N
Pyber, L
author_sort Nikolov, N
collection OXFORD
description We first note that a result of Gowers on product-free sets in groups has an unexpected consequence: If k is the minimal degree of a representation of the finite group G, then for every subset B of G with $|B| > |G| / k^{1/3}$ we have B^3 = G. We use this to obtain improved versions of recent deep theorems of Helfgott and of Shalev concerning product decompositions of finite simple groups, with much simpler proofs. On the other hand, we prove a version of Jordan's theorem which implies that if k>1, then G has a proper subgroup of index at most ck^2 for some absolute constant c, hence a product-free subset of size at least $|G| / c'k$. This answers a question of Gowers.
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spelling oxford-uuid:7ab0d965-e610-46a7-ac0c-6e8b0cd2c6bb2022-03-26T20:45:40ZProduct decompositions of quasirandom groups and a Jordan type theoremJournal articlehttp://purl.org/coar/resource_type/c_dcae04bcuuid:7ab0d965-e610-46a7-ac0c-6e8b0cd2c6bbEnglishSymplectic Elements at Oxford2007Nikolov, NPyber, LWe first note that a result of Gowers on product-free sets in groups has an unexpected consequence: If k is the minimal degree of a representation of the finite group G, then for every subset B of G with $|B| > |G| / k^{1/3}$ we have B^3 = G. We use this to obtain improved versions of recent deep theorems of Helfgott and of Shalev concerning product decompositions of finite simple groups, with much simpler proofs. On the other hand, we prove a version of Jordan's theorem which implies that if k>1, then G has a proper subgroup of index at most ck^2 for some absolute constant c, hence a product-free subset of size at least $|G| / c'k$. This answers a question of Gowers.
spellingShingle Nikolov, N
Pyber, L
Product decompositions of quasirandom groups and a Jordan type theorem
title Product decompositions of quasirandom groups and a Jordan type theorem
title_full Product decompositions of quasirandom groups and a Jordan type theorem
title_fullStr Product decompositions of quasirandom groups and a Jordan type theorem
title_full_unstemmed Product decompositions of quasirandom groups and a Jordan type theorem
title_short Product decompositions of quasirandom groups and a Jordan type theorem
title_sort product decompositions of quasirandom groups and a jordan type theorem
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