4-Hydroxy-3-methoxybenzaldehyde-nicotinamide(1/1)

In the title compound, C(6)H(6)N(2)O center dot C(8)H(8)O(3), an equimolar co-crystal of nicotinamide and vanillin, the aromatic ring and the amide fragment of the nicotinamide molecule make a dihedral angle of 32.6 (2)degrees. The vanillin molecule is almost planar, with an r.m.s. deviation for all...

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Bibliographic Details
Main Authors: How, F.N.F., Ali, Hapipah Mohd, Khaledi, H., Amalina, M.S.
Format: Article
Language:English
Published: International Union of Crystallography 2011
Subjects:
Online Access:http://eprints.um.edu.my/5231/1/How-2011-4-Hydroxy-3-methoxyb.pdf
Description
Summary:In the title compound, C(6)H(6)N(2)O center dot C(8)H(8)O(3), an equimolar co-crystal of nicotinamide and vanillin, the aromatic ring and the amide fragment of the nicotinamide molecule make a dihedral angle of 32.6 (2)degrees. The vanillin molecule is almost planar, with an r.m.s. deviation for all non-H atoms of 0.0094 angstrom. The vaniline and nicotinamide aromatic rings are nearly coplanar, the dihedral angle between them being 3.20 (9)degrees. In the crystal, the two components are linked through N-H center dot center dot center dot O and O-H center dot center dot center dot N hydrogen bonds into chains along the a axis. The chains are connected via C-H center dot center dot center dot O interactions, forming a three-dimensional polymeric structure.