Hypercyclic operators are subspace hypercyclic
In this short note, we prove that for a dense set (is a Banach space) there is a non-trivial closed subspace such that is dense in. We use this result to answer a question posed in Madore and Martínez-Avendaño (2011) [9]. In particular, we show that every hypercyclic operator is subspace-hypercyclic...
| Những tác giả chính: | , , |
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| Định dạng: | Bài viết |
| Ngôn ngữ: | English |
| Được phát hành: |
Academic Press Inc.
2016
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| Những chủ đề: | |
| Truy cập trực tuyến: | http://psasir.upm.edu.my/id/eprint/54471/1/Hypercyclic%20operators%20are%20subspace%20hypercyclic.pdf |