Discussion on the Diophantine equation X2-(a2+1)Y4=35-12a(关于丢番图方程X2-(a2+1)Y4=35-12a的讨论)
设a是正整数,证明了当a=1时,方程X2-(a2+1)Y4=35-12a仅有正整数解(X,Y)= (5,1);当α=2 时,该方程仅有正整数解(X,Y)=(4,1)和(56,5);当a=3时,该方程仅有正整数解(X,Y)=(3,1);当a=4时,该方程仅有正整数解(X,Y)= (2,1)和(202,7);当a=5时,该方程仅有1组互素的正整数解(X,Y) = (1,1);当a=6 时,该方程无正整数解(X,Y);当a≥7且12a+1为非平方数时,该方程最多有3组互素的正整数解(X,Y);当a≥7且12a+1为平方数时,该方程最多有4组互素的正整数解(X,Y)....
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Format: | Article |
Language: | zho |
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Zhejiang University Press
2016-03-01
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Series: | Zhejiang Daxue xuebao. Lixue ban |
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Online Access: | https://doi.org/10.3785/j.issn.1008-9497.2016.02.003 |